Skip to content# Compare the Triplets code challenge

### Problem

### Example

### Return

### Sample Input

### Sample Output

### Solution

## Newsletter

— 1 min read

My approach to solving HackerRank’s Compare the Triplets code challenge.

Alice and Bob each created one problem for HackerRank. A reviewer rates the two challenges, awarding points on a scale from 1 to 100 for three categories: problem clarity, originality, and difficulty.

The rating for Alice's challenge is the triplet a = (a[0], a[1], a[2]), and the rating for Bob's challenge is the triplet b = (b[0], b[1], b[2]).

The task is to find their comparison points by comparing a[0] with b[0], a[1] with b[1], and a[2] with b[2].

- If a[i] > b[i], then Alice is awarded 1 point.
- If a[i] < b[i], then Bob is awarded 1 point.
- If a[i] = b[i], then neither person receives a point.

Comparison points is the total points a person earned.

Given a and b, determine their respective comparison points.

a = [1, 2, 3]

b = [3, 2, 1]

For elements *0*, Bob is awarded a point because a[0].

For the equal elements a[1] and b[1], no points are earned.

Finally, for elements 2, a[2] > b[2] so Alice receives a point.

The return array is [1, 1] with Alice's score first and Bob's second.

`int[2]`

: Alice's score is in the first position, and Bob's score is in the second.

`15 6 723 6 10`

`11 1`

We start by creating a few variables to hold the comparison results.

Both arrays are equal in length, so we can do a for loop based on any array size. Then during each loop, we compare values of both arrays, and if `a[i]`

is bigger than `b[i]`

, then we bump `aScore`

by `1`

. Else we bump the score for `bScore`

.

Then we return the results of the scores as an array.

```
1function compareTriplets(a, b) {2 let aScore = 0,3 bScore = 0;4
5 for (let i = 0; i < a.length; i++) {6 if (a[i] > b[i]) {7 aScore++;8 } else if (a[i] < b[i]) {9 bScore++;10 }11 }12
13 return [aScore, bScore];14}
```

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