My approach to solving LeetCode’s FizzBuzz code challenge.

Problem

Given an integer n, return a string array answer (1-indexed) where:

• answer[i] == "FizzBuzz" if i is divisible by 3 and 5.
• answer[i] == "Fizz" if i is divisible by 3.
• answer[i] == "Buzz" if i is divisible by 5.
• answer[i] == i (as a string) if none of the above conditions are true.

Example

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1Input: n = 15
2Output: ["1","2","Fizz","4","Buzz","Fizz","7","8","Fizz","Buzz","11","Fizz","13","14","FizzBuzz"]

Solution

We start by creating a new temporary array (temp). Then we initialise for loop where we do have three checks to do during each iteration and push the result into the temp array.

• If the number is divisible by 3 and not 5.
• If the number is divisible by 5 and not by 3.
• If the number is divisible by 15.
• If none of the above works, we return the current iterable and convert it as a string using the template literals.

Finally, we return the temp array.

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1var fizzBuzz = function (n) {
2  const temp = [];
3
4  for (let i = 1; i <= n; i++) {
5    if (i % 3 === 0 && i % 5 !== 0) {
6      temp.push('Fizz');
7    } else if (i % 5 === 0 && i % 3 !== 0) {
8      temp.push('Buzz');
9    } else if (i % 15 === 0) {
10      temp.push('FizzBuzz');
11    } else {
12      temp.push(`${i}`);
13    }
14  }
15
16  return temp;
17};